tolong kak di jawab plis kak
7. Depan(de) = AC = b
Samping(sa) = BC = a
Miring(mi) = AB = c
a. sin α = de/mi = AC/AB = b/c
cos α = sa/mi = BC/AB = a/c
tan α = de/sa = AC/BC = b/a
b. AC = 5 cm, AB = 3 cm
BC² = AB² - AC²
= 3² - 5²
= 9 - 25
= -16
BC = √-16
sin α = de/mi = AC/AB = 5/√-16
[tex] = \frac{5}{ \sqrt{ - 16} } \times \frac{ \sqrt{ - 16} }{ \sqrt{ - 16} } \\ = \frac{ 5}{ - 16} \sqrt{ - 16 } \\ = - \frac{5}{16} \sqrt{ - 16} [/tex]
cos α = sa/mi = BC/AB = 3/√-16
[tex] = \frac{3}{ \sqrt{ - 16} } \times \frac{ \sqrt{ - 16} }{ \sqrt{ - 16} } \\ = \frac{3}{ - 16} \sqrt{ - 16} \\ = - \frac{3}{16} \sqrt{ - 16} [/tex]
tan α = de/sa = AC/BC = 5/3
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